Ausgabe der neuen DB Einträge

venv/lib/python3.9/site-packages/twisted/web/script.py

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+# -*- test-case-name: twisted.web.test.test_script -*-
+# Copyright (c) Twisted Matrix Laboratories.
+# See LICENSE for details.
+
+"""
+I contain PythonScript, which is a very simple python script resource.
+"""
+
+from __future__ import division, absolute_import
+
+import os, traceback
+
+from twisted import copyright
+from twisted.python.filepath import _coerceToFilesystemEncoding
+from twisted.python.compat import execfile, networkString, NativeStringIO, _PY3
+from twisted.web import http, server, static, resource, util
+
+
+rpyNoResource = """<p>You forgot to assign to the variable "resource" in your script. For example:</p>
+<pre>
+# MyCoolWebApp.rpy
+
+import mygreatresource
+
+resource = mygreatresource.MyGreatResource()
+</pre>
+"""
+
+class AlreadyCached(Exception):
+    """
+    This exception is raised when a path has already been cached.
+    """
+
+class CacheScanner:
+    def __init__(self, path, registry):
+        self.path = path
+        self.registry = registry
+        self.doCache = 0
+
+    def cache(self):
+        c = self.registry.getCachedPath(self.path)
+        if c is not None:
+            raise AlreadyCached(c)
+        self.recache()
+
+    def recache(self):
+        self.doCache = 1
+
+noRsrc = resource.ErrorPage(500, "Whoops! Internal Error", rpyNoResource)
+
+def ResourceScript(path, registry):
+    """
+    I am a normal py file which must define a 'resource' global, which should
+    be an instance of (a subclass of) web.resource.Resource; it will be
+    renderred.
+    """
+    cs = CacheScanner(path, registry)
+    glob = {'__file__': _coerceToFilesystemEncoding("", path),
+            'resource': noRsrc,
+            'registry': registry,
+            'cache': cs.cache,
+            'recache': cs.recache}
+    try:
+        execfile(path, glob, glob)
+    except AlreadyCached as ac:
+        return ac.args[0]
+    rsrc = glob['resource']
+    if cs.doCache and rsrc is not noRsrc:
+        registry.cachePath(path, rsrc)
+    return rsrc
+
+
+
+def ResourceTemplate(path, registry):
+    from quixote import ptl_compile
+
+    glob = {'__file__': _coerceToFilesystemEncoding("", path),
+            'resource': resource.ErrorPage(500, "Whoops! Internal Error",
+                                           rpyNoResource),
+            'registry': registry}
+
+    with open(path) as f:  # Not closed by quixote as of 2.9.1
+        e = ptl_compile.compile_template(f, path)
+    code = compile(e, "<source>", "exec")
+    eval(code, glob, glob)
+    return glob['resource']
+
+
+
+class ResourceScriptWrapper(resource.Resource):
+
+    def __init__(self, path, registry=None):
+        resource.Resource.__init__(self)
+        self.path = path
+        self.registry = registry or static.Registry()
+
+    def render(self, request):
+        res = ResourceScript(self.path, self.registry)
+        return res.render(request)
+
+    def getChildWithDefault(self, path, request):
+        res = ResourceScript(self.path, self.registry)
+        return res.getChildWithDefault(path, request)
+
+
+
+class ResourceScriptDirectory(resource.Resource):
+    """
+    L{ResourceScriptDirectory} is a resource which serves scripts from a
+    filesystem directory.  File children of a L{ResourceScriptDirectory} will
+    be served using L{ResourceScript}.  Directory children will be served using
+    another L{ResourceScriptDirectory}.
+
+    @ivar path: A C{str} giving the filesystem path in which children will be
+        looked up.
+
+    @ivar registry: A L{static.Registry} instance which will be used to decide
+        how to interpret scripts found as children of this resource.
+    """
+    def __init__(self, pathname, registry=None):
+        resource.Resource.__init__(self)
+        self.path = pathname
+        self.registry = registry or static.Registry()
+
+    def getChild(self, path, request):
+        fn = os.path.join(self.path, path)
+
+        if os.path.isdir(fn):
+            return ResourceScriptDirectory(fn, self.registry)
+        if os.path.exists(fn):
+            return ResourceScript(fn, self.registry)
+        return resource.NoResource()
+
+    def render(self, request):
+        return resource.NoResource().render(request)
+
+
+
+class PythonScript(resource.Resource):
+    """
+    I am an extremely simple dynamic resource; an embedded python script.
+
+    This will execute a file (usually of the extension '.epy') as Python code,
+    internal to the webserver.
+    """
+    isLeaf = True
+
+    def __init__(self, filename, registry):
+        """
+        Initialize me with a script name.
+        """
+        self.filename = filename
+        self.registry = registry
+
+    def render(self, request):
+        """
+        Render me to a web client.
+
+        Load my file, execute it in a special namespace (with 'request' and
+        '__file__' global vars) and finish the request.  Output to the web-page
+        will NOT be handled with print - standard output goes to the log - but
+        with request.write.
+        """
+        request.setHeader(b"x-powered-by", networkString("Twisted/%s" % copyright.version))
+        namespace = {'request': request,
+                     '__file__': _coerceToFilesystemEncoding("", self.filename),
+                     'registry': self.registry}
+        try:
+            execfile(self.filename, namespace, namespace)
+        except IOError as e:
+            if e.errno == 2: #file not found
+                request.setResponseCode(http.NOT_FOUND)
+                request.write(resource.NoResource("File not found.").render(request))
+        except:
+            io = NativeStringIO()
+            traceback.print_exc(file=io)
+            output = util._PRE(io.getvalue())
+            if _PY3:
+                output = output.encode("utf8")
+            request.write(output)
+        request.finish()
+        return server.NOT_DONE_YET